I need help with my question...(I am a true algebra student!)?

What is the solution to x=1/3y+2 that also has to be a solution to -2x-y=1? It is supposed to be in coordinates! or just like x=_ %26amp; y=_I need help with my question...(I am a true algebra student!)?
x = (1/3)y + 2


-2x - y = 1





Take the first equation, and plug its value of x into the second eq.





-2[(1/3)y+2] - y = 1





Simplify





(-2/3)y - 4 - y = 1





(-2/3)y - y = 5





(-5/3)y = 5





y = -3





Using the value of y, solve for x.





x = (1/3)(-3) + 2


x = (-1) + 2


x = 1





So, the ANSWER is x=1 %26amp; y=-3